Which alkene undergoes ozonolysis to produce | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Ozonolysis of an alkene involves the cleavage of the $C=C$ double bond to form carbonyl compounds.For a cyclic alkene,ozonolysis results in an ope

Vedclass · Accepted Answer

$1,2-$dimethylcyclohexene

Vedclass · Answer

(D) Ozonolysis of an alkene involves the cleavage of the $C=C$ double bond to form carbonyl compounds.For a cyclic alkene,ozonolysis results in an open-chain dicarbonyl compound.$2,6-$heptanedione is a $7-$carbon chain with ketone groups at positions $2$ and $6$.The structure is $CH_3-CO-CH_2-CH_2-CH_2-CO-CH_3$.This indicates that the original alkene was a cyclic compound with a $7-$carbon ring containing a double bond,specifically $1,2-$dimethylcyclohexene,where the double bond is between the carbons bearing the methyl groups. Upon ozonolysis,the $C=C$ bond breaks,and the ring opens to form the $7-$carbon chain with carbonyls at the ends of the original double bond positions.

Which alkene undergoes ozonolysis to produce $2,6-$heptanedione?

Similar Questions

What is the correct order of reactivity of alkenes towards acid-catalyzed hydration to form alcohols?

In hydroboration reaction:
$I$. $Syn$ addition takes place
$II$. Reaction proceeds through formation of a cyclic transition state
$III$. Markovnikov rule is followed in the reaction
$IV$. Anti-addition takes place and anti-Markovnikov rule is followed
Which statement$(s)$ is/are correct?

What is $X$ in the given reaction?
$HOCH_2-CH_2OH + (COOH)_2 \xrightarrow{210^{\circ}C} X$
(major product)

The alkene $R-CH=CH_2$ reacts readily with $B_2H_6$ and forms the product $B$,which on oxidation with alkaline hydrogen peroxide produces:

In the presence of peroxide,hydrogen chloride or hydrogen iodide do not give anti-Markovnikov addition to alkenes because...

Vedclass Test Series

Exam Paper Generator

Online Exam Module